Math Help!! Trigonometry.

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I don't if anybody is good at trig, can't find any other help so I'm asking here. thanks. Simplify: cosx/(secx-1). Thanks!
 

Mr. Satchmo

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never mind, I'm obviously an ignoramus at trigonometry haha

looks like outlaw go it
 

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cos(x)/[sec(x) - 1] + cos(x)/[sec(x) + 1]
= cos(x)[1/cos(x) - 1] + cos(x)/[1/cos(x) + 1]
= cos²(x)/[1 - cos(x)] + cos²(x)/[1 + cos(x)]
= {cos²(x)[1 + cos(x)]}/{[1 + cos(x)][1 - cos(x)]} + cos²(x)[1 - cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= cos²(x) * [1 + cos(x) + 1 - cos(x)]/[1 - cos²(x)]
= cos²(x) * 2/[1 - cos²(x)]
= cos²(x) * 2/sin²(x)
= 2cos²(x)/sin²(x)
= 2[cos(x)/sin(x)]²
Answer = 2cot²(x).
 

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I have trouble adding up my score on a golf hole.
 

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Not following where you raised sec to the -1... edit: to satch.

Outlaw, you copied that of yahoo answers and that's the wrong problem.
 

Mr. Satchmo

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Me or you? haha
 

Mr. Satchmo

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No that's a problem he copied from yahoo answers and is the wrong problem in the beginning.
 

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GHIN 5.5
cos(x)/[sec(x) - 1] + cos(x)/[sec(x) + 1]
= cos(x)[1/cos(x) - 1] + cos(x)/[1/cos(x) + 1]
= cos²(x)/[1 - cos(x)] + cos²(x)/[1 + cos(x)]
= {cos²(x)[1 + cos(x)]}/{[1 + cos(x)][1 - cos(x)]} + cos²(x)[1 - cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= cos²(x) * [1 + cos(x) + 1 - cos(x)]/[1 - cos²(x)]
= cos²(x) * 2/[1 - cos²(x)]
= cos²(x) * 2/sin²(x)
= 2cos²(x)/sin²(x)
= 2[cos(x)/sin(x)]²
Answer = 2cot²(x).

That's Egyptian hieroglyphs.....right ?

If not...you are speaking a language to which I am not accustomed.
 

JF

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He nailed the answer, gotta give him props for that (copied or not).

I'll grab some scratch paper and try to work it out for you Riley. Do you need the steps or just the answer?


THPing on Tapatalk
 

TMAdidas

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Crap, I take trig next year, I'm screwed if it's like this :(..
 

TeedUpThoughts

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Why does your math have letters?? Lol, trig is/never was my strong suit, good luck!!


On my iPhone T.. T.. Tapatalking away!
 

JF

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Why does your math have letters?? Lol, trig is/never was my strong suit, good luck!!


On my iPhone T.. T.. Tapatalking away!
Ratios in the triangle. It's painful stuff I know.

Sorry dude, it's not coming to me. Anything I come up with seems wrong. It's been a long while since I did this last year.


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I got a headache just looking at the problem.


Sent from my iPhone using Tapatalk 2
 

Darren K.

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GHIN 14.3

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The answer is 8.

Right?
 

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blugold

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Wake

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blugold

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I'm changing my answer, its the 85 bears.

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Ditka will find a way to get it done.
 

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